Question
Q 1 . Change the following polar equations into Cartesian equations:
(a) r = a sin 2 A
(b) A=π/4
(a) r = a sin 2 A
(b) A=π/4
Answers
Steve
If you are using A for θ, then clearly θ=π/4 is a straight line with slope 1, so that is just
y = x
r = a sin2θ
r = 2a sinθ cosθ
r^3 = 2a rsinθ rcosθ
(x^2+y^2)^(3/2) = axy
But that only gives half of the graph, where xy is positive.
y = x
r = a sin2θ
r = 2a sinθ cosθ
r^3 = 2a rsinθ rcosθ
(x^2+y^2)^(3/2) = axy
But that only gives half of the graph, where xy is positive.
jaykant
soliction
jaykant
(a) r = a sin 2 A
(b) A=π/4soliction
(b) A=π/4soliction