Asked by ammu
Two pipes A and B can fill in 40 minutes and 30 minutes respectively.Both the pipes are open together but after 5 minutes, pipe B is turned off.What is the total time required to fill the tank?
Answers
Answered by
Steve
we see that both pipes together can fill the the tank in 120/7 minutes:
1/t = 1/40 + 1/30
t = 7/120
So, after 5 minutes, they have filled 35/120 = 7/24 of the tank.
So, it will take A 7/24*40 = 35/3 minutes to fill the rest.
Total time: 5 + 35/3 = 16 2/3 minutes.
1/t = 1/40 + 1/30
t = 7/120
So, after 5 minutes, they have filled 35/120 = 7/24 of the tank.
So, it will take A 7/24*40 = 35/3 minutes to fill the rest.
Total time: 5 + 35/3 = 16 2/3 minutes.
Answered by
Henry
T = Ta*Tb/(Ta+Tb) = 40*30/(40+30)= 17.14 Min. to fill with both pipes open.
(17.14-5)/17.14 = 0.708 of a tank
to be filled.
5 + 0.708*40 = 33.34 Min., total.
(17.14-5)/17.14 = 0.708 of a tank
to be filled.
5 + 0.708*40 = 33.34 Min., total.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.