Asked by Jen
ABC is a right triangle. Angle C is 90 degree.
Altitude CD is drawn to hypotenuse AB.
Prove AB/BC = BC/BD and AB/AC = AC/AD
This is a theorem. How do I prove it? Thanks.
Dont you have similar triangles? You can show this by looking at the angles involved...remember the altitude forms a perpendicular angle on the hypotenuse.
Altitude CD is drawn to hypotenuse AB.
Prove AB/BC = BC/BD and AB/AC = AC/AD
This is a theorem. How do I prove it? Thanks.
Dont you have similar triangles? You can show this by looking at the angles involved...remember the altitude forms a perpendicular angle on the hypotenuse.
Answers
Answered by
Anonymous
ABC WITH A=35,AC=6cm and C=65 a second triangle wit G=80,GH=9cm and H=35
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