Asked by Kyle
                Find a cubic function 
y = ax3 + bx2 + cx + d
whose graph has horizontal tangents at the points
            
        y = ax3 + bx2 + cx + d
whose graph has horizontal tangents at the points
Answers
                    Answered by
            bobpursley
            
    well, horizontal tangent,y'=0
y'=0=3ax^2+bx+c
so you solve that quadratic equation
x=(-b+-sqrt(b^2-4ac))/2a
    
y'=0=3ax^2+bx+c
so you solve that quadratic equation
x=(-b+-sqrt(b^2-4ac))/2a
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.