Question

If you randomly choose two different numbers from 1 to 10, what is the probability that one number is one more than the other?

Answers

bobpursley
If they are different numbers, the probability that one is greater than the other one is equal to 1.
Goodness.
Reiny
you could have picked 1-2, 2-3, 3-4, 4-5, 5-6 , 6-7, 7-8, 8-9, 9-10 or their reverses.

so prob(your event) = 18/100 = 9/50
jhepoy
1/5

tangina basta yan ung tama
ME25
There are 10!/8!2!=45 possible combinations that you will get given that you draw two numbers at a time. Then, there are possible combinations you could draw where numbers are consecutive e.g. (1,2),(2,3),(3,4),(4,5),(5,6),(6,7),(7,8),(8,9),(9,10) and vice-versa for a total of 9 possible combinations. Thus, the probability that one number is one more than the other is 9/45 or 1/5. Hope it helps. :)

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