Asked by manilen
simplify √(23+√408) -√(23-√408) ?
Answers
Answered by
Damon
LOL
a^2 - b^2 = (a+b)(a-b)
so
23 - 408 = (sqrt(23) -sqrt....
a^2 - b^2 = (a+b)(a-b)
so
23 - 408 = (sqrt(23) -sqrt....
Answered by
Alfred
Let 23=x
408=y
N= final answer
then
√(23+√408) - √(23-√408) becomes
√(x+√y) - √(x-√y)
Equating it to N
√(x+√y) - √(x-√y)=N
Solving this,
N²= 2x-2√(x²-y)
Subsituting x=23 and y=408
N²=2(23)-2√(23²-408)
=46-2√(529-408)
=46-2√121
=46-2(11)
=46-22
=24
N²=24
N=2√6.
I hope it helps.
408=y
N= final answer
then
√(23+√408) - √(23-√408) becomes
√(x+√y) - √(x-√y)
Equating it to N
√(x+√y) - √(x-√y)=N
Solving this,
N²= 2x-2√(x²-y)
Subsituting x=23 and y=408
N²=2(23)-2√(23²-408)
=46-2√(529-408)
=46-2√121
=46-2(11)
=46-22
=24
N²=24
N=2√6.
I hope it helps.
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