Asked by Divine phyavuh
If 6.00g of carbon is heated in air, the mass of the product obtained could either be 22.0g or 14.6g depending on the amount of air present. Using calculations with what law will this be in accordance?
Answers
Answered by
bobpursley
Proust's law or the law of definite composition.
6 gram C is 1/2 mole, the remaining 16 gram is 1 mole O, yielding 1/2 mole of CO2.
6 gram C is 1/2 mole, the remaining 8.6 g represents CO. I suspect there is a typo error here, instead of 14.6 it should have been 14.0
6 gram C is 1/2 mole, the remaining 16 gram is 1 mole O, yielding 1/2 mole of CO2.
6 gram C is 1/2 mole, the remaining 8.6 g represents CO. I suspect there is a typo error here, instead of 14.6 it should have been 14.0
Answered by
Rhema
Pls explain
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