Asked by Brittany
You wish to prepare 0.18 M HNO3 from a stock solution of nitric acid that is 18.9 M. How many milliliters of the stock solution do you require to make up 1.00 L of 0.18 M HNO3?
Answers
Answered by
DrBob222
M x mL = M x mL.
18.9 M x mL = 0.18 M x 1000 mL
18.9 M x mL = 0.18 M x 1000 mL
Answered by
Brittany
I don't understand what to do.
Answered by
~christina~
solve for ml
(it's a dilution equation)
You have the initial concentration and final concentration with volume of it that you want. All you need is the initial volume of concentrated nitric acid you want to remove from the concentrated stock volume, to use to dilute to the needed concentration.
(it's a dilution equation)
You have the initial concentration and final concentration with volume of it that you want. All you need is the initial volume of concentrated nitric acid you want to remove from the concentrated stock volume, to use to dilute to the needed concentration.
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