Asked by Leah
                Given cosθ=3/7 and 0≤θ≤π/2 find sinθ and tanθ
            
            
        Answers
                    Answered by
            Damon
            
    sin^2 T = 1 - cos^2 T
sin^2 T = 1 - 9/49
sin^2 T = 40/49
sin T = (2/7) sqrt 10
and tan T = sin T/cos T
    
sin^2 T = 1 - 9/49
sin^2 T = 40/49
sin T = (2/7) sqrt 10
and tan T = sin T/cos T
                    Answered by
            Steve
            
    or, just draw the triangle and label the sides. The missing side is √(49-9) = √40
Then you can read off all the trig functions just by looking at the sides and using the proper ones.
    
Then you can read off all the trig functions just by looking at the sides and using the proper ones.
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