Asked by Leah
Given cosθ=3/7 and 0≤θ≤π/2 find sinθ and tanθ
Answers
Answered by
Damon
sin^2 T = 1 - cos^2 T
sin^2 T = 1 - 9/49
sin^2 T = 40/49
sin T = (2/7) sqrt 10
and tan T = sin T/cos T
sin^2 T = 1 - 9/49
sin^2 T = 40/49
sin T = (2/7) sqrt 10
and tan T = sin T/cos T
Answered by
Steve
or, just draw the triangle and label the sides. The missing side is √(49-9) = √40
Then you can read off all the trig functions just by looking at the sides and using the proper ones.
Then you can read off all the trig functions just by looking at the sides and using the proper ones.