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A centrifuge rotor rotating at 12000 rpm is shut off and is eventually brought to rest by a frictional torque of 1.50 m·N. If the mass of the rotor is 4.80 kg and it can be approximated as a solid cylinder of radius 0.0710 m, through how many revolutions will the rotor turn before coming to rest? How long will it take?
Answered by bobpursley
a. calculate the moment of inertia for the rotor (solid cylinder). Personnally, I recmmmend changing rpm to radians/sec

Torque=momentI* angular acceleration
solve for angular acceleration.

Then,
wfinal=winitial+ angAcc*time
solve for time

displacement=winitial*time+1/2 angacc;*time^2
solve for displacement in radians, divide by 2PI to get revolutions.
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