Asked by Fred
Which of the following integrals represents the volume of the solid formed by revolving the region bounded by y=x^3, y=1, and x=2 about the line y=10?
a) pi*∫from (8-1) of (10-y)(2-y^(1/3))dy
b) pi*∫ from (1-2) of (81-(10-x^3)^2)dx
c)2pi*∫from (1-8) of y(2-y^(1/3))dy
d) pi∫ from (1-2) of (1-(10-x^3)^2)dx
e)2pi*∫from (1-8) of (y+9)(10-y^3)dy
a) pi*∫from (8-1) of (10-y)(2-y^(1/3))dy
b) pi*∫ from (1-2) of (81-(10-x^3)^2)dx
c)2pi*∫from (1-8) of y(2-y^(1/3))dy
d) pi∫ from (1-2) of (1-(10-x^3)^2)dx
e)2pi*∫from (1-8) of (y+9)(10-y^3)dy
Answers
Answered by
Steve
y=1, and x=2
Bogus limits. Fix one or the other.
In any case, the radius is 10-y and v = pi r^2 h
Bogus limits. Fix one or the other.
In any case, the radius is 10-y and v = pi r^2 h
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