Asked by tammy

Mr. Jackson is preparing bags of treats to give trick or treaters on Halloween. He has 48 pieces of candy and 60 pieces of gum. He uses all the candy and gum, and he puts the same ratio of candy to gum in each bag. What is the largest number of bags he could have made?
Answered by bobpursley
What is the smallest common factor of 48 and 60? I will be happy to check your thinking.
Answered by tammy
48, but it says he uses all the candy and gum
Answered by bobpursley
The smallest common factor of each is 2, 3, 4, and up. Now the trick is to look at the ratio

48/60=reduces to 3/4 Since both the numberator and the denominator are common factors, then use these: 3 pieces of candy and 4 pieces of gum. Now you can answer the question.
Answered by helen
13 because 48/60 reduces to 4/5.THE ANSWER IS EITHER 12 OR 13. NOT 7!!!
Answered by amanda
I got 12
Answered by Jeni
1f he made 6 bags, with 8 pieces of candy and 10 pieces of gum in each, that would work. But thats alot for each bag. reduce 8/10 to 4/5 and you can make 12 bags.
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