work = force in the direction of motion
* distance
normal force down = weight - tension component up
= m g - F sin 23
friction force = .33(mg-F sin 23)
drag force = F cos 23
no accelration so friction force = drag force
F cos 23 = .33 (mg-F sin 23)
solve for F
we want the horizontal component of F
for the work
work = F cos 23 * 5.25
the end
You pull a 30.5 kg wooden box with a rope that makes a 23.0° angle with the horizontal at a constant speed. The coefficient of kinetic friction between the box and the deck is 0.330. You pull the crate a distance of 5.25 m. How much work was done?
Do you use f=ma and how does the angle get used in this equation?
3 answers
By the way is a physic something you take for a stomach ache?
http://www.thefreedictionary.com/physic
1 answer