Asked by Edge
The radius of the earth's orbit around the sun (assumed to be circular) is 1.50 X 108 km, and the earth travels around this orbit in 365 days. (a) What is the magnitude of the orbital velocity of the earth, in m/s? (b) What is the radial acceleration of the earth toward the sun, in m/s2? (c) Repeat parts (a) and (b) for the motion of the planet Mercury (orbit radius = 5.79 X 107 km, orbital period = 88.0 days)
Answers
Answered by
Damon
r = 1.5 * 10^11 meters
2 pi r = 9.42 * 10^11 meters circumference
and
365d * 24h/d * 3600 s/h =3.15 * 10^7 seconds
v = 9.42*10^11 m/3.15*10^7 s = 2.99*10^4 m/s
Ac = v^2/r
etc
2 pi r = 9.42 * 10^11 meters circumference
and
365d * 24h/d * 3600 s/h =3.15 * 10^7 seconds
v = 9.42*10^11 m/3.15*10^7 s = 2.99*10^4 m/s
Ac = v^2/r
etc
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.