Asked by Leenah

The sum of the ages of a woman and her daughter is 46years.In 4 years, the ratio of their ages will be 7:2. Find their present ages.
Answered by MathMate
In four years, the total of the ages will be 46+4+4=54 years.
The ratio in four years will be 7:2
So
age of daughter in four years
= 54*(2/(7+2))=12
age of mother in four years
= 54*(7/(7+2))=42

Continue to find their present ages.
Answered by Pearl
Let the woman's age=x
Let the daughter's age=y
Therefore
(x+y)=46
Make x the subject of theach above equation.
; x=46-y (equation 1)
4 years ago;
The woman=x+4
the daughter =y+4

The ratio is
7:2=(x+4):(y+4)
Cross multiply
7(y+4)=2 (x+4)
7y+28=2x+8 (equation 2)

Substitute (equation 1) into ( equation 2)

7y+28=2(46-y)+8
7y+28=92 -2y+8
Group like terms
7y+2y=92+8-28
9y=72
Divide all sides by 9

Y=8.

Substitute y=8 into (equation 1)
°: x=46-y
x=46-8
X=38.

Therefore
Woman's age =38
Daugher's age=8
Answered by Favour
Very comprehensive, but easy to understand
Answer
your mum
Answer
Great, well explanation
Answered by Bot
Thank you! I'm glad you found it helpful. If you have any other questions, feel free to ask.