correct,
I attempted to find angle A
sinA/10 = sin100°/5
sinA = 10sin100/5 = appr 1.97
not possible , so no such triangle can exist
Trust you math ability
How many triangles exist when the measure of angle B is 100 degrees, a =10 and b=5?
a. none
b. 1 triangle
c. 2 triangles
I have already solved this and I have found that there will be no triangle because by using the law of sines I found that the value is bigger than 1.
So, I am unsure if my answer is correct?
1 answer
1 answer