Asked by Pandu
the pH of a solution is 10 and other is 12 when equal volumes of these low are mixed the pH of the resulting solution is?
Answers
Answered by
DrBob222
"equal volumes of these low" WHAT?
If the acids are strong acids we can take 100 mL of each.
For pH = 10 we have 100 x 1E-10 = 1E-8 millimols.
Add 100 mL pH = 12 and we have 100 x 1E-10 millimols.
Add 1E-8 mmols and 1E-10 mmols = 1.01E-8 millimols and that is in 200 mL so
(H^+) = 1E-8 mmols/200 mL = 5.05E-11 and pH = ?. About 10.3
You can use 50 mL each or 1000 mL each ( or any equal numbers) and the answer will be the same.
If the acids are strong acids we can take 100 mL of each.
For pH = 10 we have 100 x 1E-10 = 1E-8 millimols.
Add 100 mL pH = 12 and we have 100 x 1E-10 millimols.
Add 1E-8 mmols and 1E-10 mmols = 1.01E-8 millimols and that is in 200 mL so
(H^+) = 1E-8 mmols/200 mL = 5.05E-11 and pH = ?. About 10.3
You can use 50 mL each or 1000 mL each ( or any equal numbers) and the answer will be the same.