Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
A block of mass 3kg which is on a smooth inclined plane making an angle of 30° to the horizontal is connected by a cord passing...Asked by swati
A block of mass 3kg which is on a smooth inclined plane making an angle of 30° to the horizontal is connected by a cord passing over a light frictionless pulley to a second block of mass 2kg hanging vertically. What is the acceleration of each block and what is the tention of thr cord?
Answers
Answered by
Damon
The 2 kg hanging block:
x defined down
m a = m g - T
T = m (g-a)
T = 2 (9.81-a)
The 3 kg bock on the slope:
now x is up the slope
T - m g sin 30 = m a
T = m (g/2+a)
T = 3 (4.9-a)
your turn.
x defined down
m a = m g - T
T = m (g-a)
T = 2 (9.81-a)
The 3 kg bock on the slope:
now x is up the slope
T - m g sin 30 = m a
T = m (g/2+a)
T = 3 (4.9-a)
your turn.
Answered by
Anonymous
And is in complete
Answered by
Anonymous
Stupid answer it's wrong
Answered by
Bhanu teja
m1gsin30=3×9.8×1/2=14.7 (take g=9.8)
m2g=2×9.8=19.6
14.7-T=3a --------(1)
T-19.6=2a ---------(2)
By solving 1 and 2 we get a=-4.9
(-) indicates direction
a=4.9
By substituting a=4.9 in any equation,we get T=17.6N
m2g=2×9.8=19.6
14.7-T=3a --------(1)
T-19.6=2a ---------(2)
By solving 1 and 2 we get a=-4.9
(-) indicates direction
a=4.9
By substituting a=4.9 in any equation,we get T=17.6N
Answered by
Jaswanth
a=0.98m/s2
Answered by
Anonymous
stupid donkey wrong answer
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.