Asked by swati

A block of mass 3kg which is on a smooth inclined plane making an angle of 30° to the horizontal is connected by a cord passing over a light frictionless pulley to a second block of mass 2kg hanging vertically. What is the acceleration of each block and what is the tention of thr cord?

Answers

Answered by Damon
The 2 kg hanging block:
x defined down
m a = m g - T
T = m (g-a)
T = 2 (9.81-a)

The 3 kg bock on the slope:
now x is up the slope
T - m g sin 30 = m a
T = m (g/2+a)
T = 3 (4.9-a)
your turn.
Answered by Anonymous
And is in complete
Answered by Anonymous
Stupid answer it's wrong
Answered by Bhanu teja
m1gsin30=3×9.8×1/2=14.7 (take g=9.8)
m2g=2×9.8=19.6
14.7-T=3a --------(1)
T-19.6=2a ---------(2)
By solving 1 and 2 we get a=-4.9
(-) indicates direction
a=4.9
By substituting a=4.9 in any equation,we get T=17.6N
Answered by Jaswanth
a=0.98m/s2
Answered by Anonymous
stupid donkey wrong answer
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