Asked by Jason
Obtaining an algebraic Equation for T
(0.300)(4190J/(kg*K)(T-70.0*C) +
(0.100)(390J)/(kg*K)(T-20.0*C)
I don't know how to use the Algebraic Equation on that?
(0.300)(4190J/(kg*K)(T-70.0*C) +
(0.100)(390J)/(kg*K)(T-20.0*C)
I don't know how to use the Algebraic Equation on that?
Answers
Answered by
Steve
suppressing all those units, we have
(.300)(4190)(T-70) + (.100)(390)(T-20)
= 1257T - 87990 + 39T-780
= 1296T - 88770
You can do with that what you will
(.300)(4190)(T-70) + (.100)(390)(T-20)
= 1257T - 87990 + 39T-780
= 1296T - 88770
You can do with that what you will