Question

The first three terms of GP are x+1,(x^2-1) and (x^2-1)(2x-4).Calculate the value of x. Suggested solution;ar^2/ar,so r=2x-4 and a=x+1. Substitute in second term(ar)=(x^2-1). Factorise, so x=3

Answer 1

Your solution for x = 3 is correct,
now all you have to do is sub x = 3 into your 3 terms to get
4, 8, 16

you already knew r = 2 from r = 2(3) - 4 = 2
and a = 4 from a = x+1 = 4

Answer 2

Thanks Reiny.