Asked by Ques
A gram molecule of a gas at 127°C expands isothermally until its volume is doubled. Find the amount of work done and heat absorbed.
Answers
Answered by
Farohw
The formula you will use for isothermic expansion is:
Work(W) = 2.303 RT log(V2/V1)
Let R = 8.3 J / mole-K (universal gas constant and V2/v1 = 2/1 = 2.
Converting temperature to Kelvins:
T = 127°C = 400K
Work(W) = (2.3)(8.3)(400)log(2)
W = 2.3 x 10^3 J
To find the heat absorbed:
2.3 x 10^3 J/4.2 = 548 cal.
Work(W) = 2.303 RT log(V2/V1)
Let R = 8.3 J / mole-K (universal gas constant and V2/v1 = 2/1 = 2.
Converting temperature to Kelvins:
T = 127°C = 400K
Work(W) = (2.3)(8.3)(400)log(2)
W = 2.3 x 10^3 J
To find the heat absorbed:
2.3 x 10^3 J/4.2 = 548 cal.
Answered by
Ashim
One gram molecule of an ideal gas at 127°C expands isothermally until volume is doubled ,find the amount of work done given log=0.3010 R=8.31×10erg mol-¹°c
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