Asked by Collins
4x^2+8x-m=0,differs by 3 find the value of the constant m
plz help me??
plz help me??
Answers
Answered by
Damon
differs from what by 3 ?
do you mean the roots differ by 3 or something?
do you mean the roots differ by 3 or something?
Answered by
Collins
Yes the root
Answered by
Damon
ok
x = [ -8+/- sqrt (64-16m) ]/8
so
(1/8) * 2 * sqrt (64-16 m) = 3
sqrt (64 - 16 m) = 12
64 - 16 m = 144
16 m = 80
m = 5
x = [ -8+/- sqrt (64-16m) ]/8
so
(1/8) * 2 * sqrt (64-16 m) = 3
sqrt (64 - 16 m) = 12
64 - 16 m = 144
16 m = 80
m = 5
Answered by
Collins
If
64-16m=144
-16m=80
m=-5? Can it be negative
64-16m=144
-16m=80
m=-5? Can it be negative
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