Asked by Collins
The earth moves round the sun in one year.the average earth-sun distance is 1.5*10^11m given that the mass of the earth is 5.98*10^24kg
(a):the angular momentum of the earth???
(b):kinetic energy of the earth motion??
(c):kinetic energu of the earth motion half way along it axis???
Please help me it too difficult
(a):the angular momentum of the earth???
(b):kinetic energy of the earth motion??
(c):kinetic energu of the earth motion half way along it axis???
Please help me it too difficult
Answers
Answered by
bobpursley
a. Angular amomentum= mr^2*w
= M r^2*2PI/yearinseconds
b. KE=1/2 I w^2=1/2 Mr^2 (2PI/yearinsecons)^2
c. I am not certain what "its" axis refers to, but I think someone is wanting you to use the parallel axis theorm.
= M r^2*2PI/yearinseconds
b. KE=1/2 I w^2=1/2 Mr^2 (2PI/yearinsecons)^2
c. I am not certain what "its" axis refers to, but I think someone is wanting you to use the parallel axis theorm.
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