Asked by Sally
During its first week of business, a market sold a total of 108 apples and oranges. The second week, five times the number of apples and three times the number of oranges were sold. A total of 452 apples and oranges were sold during the second week. Determine how many apples and how many oranges were sold the first week.
Answers
Answered by
Bosnian
a = apples
o = oranges
1 week :
a + o = 108
2 week :
5 a + 3 o = 452
Now you must solve system of 2 equations with 2 unknown :
a + o = 108
5 a + 3 o = 452
The method of substitution:
a + o = 108 Subtract o to both sides
a + o - o = 108 - o
a = 108 - o
5 a + 3 o = 452
5 * ( 108 - o ) + 3 o = 452
5 * 108 - 5 * o + 3 o = 452
540 - 5 o + 3 o = 452
540 - 2 o = 452 Subtract 540 to both sides
540 - 2 o - 540 = 452 - 540
- 2 o = - 88 Divide both sides by - 2
- 2 o / - 2 = - 88 / - 2
o = 44
a = 108 - o
a = 108 - 44 = 64
64 apples and 44 oranges
o = oranges
1 week :
a + o = 108
2 week :
5 a + 3 o = 452
Now you must solve system of 2 equations with 2 unknown :
a + o = 108
5 a + 3 o = 452
The method of substitution:
a + o = 108 Subtract o to both sides
a + o - o = 108 - o
a = 108 - o
5 a + 3 o = 452
5 * ( 108 - o ) + 3 o = 452
5 * 108 - 5 * o + 3 o = 452
540 - 5 o + 3 o = 452
540 - 2 o = 452 Subtract 540 to both sides
540 - 2 o - 540 = 452 - 540
- 2 o = - 88 Divide both sides by - 2
- 2 o / - 2 = - 88 / - 2
o = 44
a = 108 - o
a = 108 - 44 = 64
64 apples and 44 oranges
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