Asked by Elisha
what volume of 0.1M HCl would be needed to neutralize 0.35M NaOH to a 100ml volume?
Answers
Answered by
bobpursley
The normality of both is one, so
1*.1M*VolumeACid=1*.35M*100ml
VolumeAcid=350ml
1*.1M*VolumeACid=1*.35M*100ml
VolumeAcid=350ml
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.