Asked by bear
vs =6 volts
vth =2 volts
ida(diode current)=1m amp
no value given for resistor network
find rth(thevenien)
2,000 and 4000 do not work.
diode current must not be equal to isc.??
voc=2 volts
vth =2 volts
ida(diode current)=1m amp
no value given for resistor network
find rth(thevenien)
2,000 and 4000 do not work.
diode current must not be equal to isc.??
voc=2 volts
Answers
Answered by
Henry
Diode Connected:
Vd + (I2+Id)R1 = 6 Volts.
0.7 + (I2+1.0)R1 = 6.
0.7 + I2*R1 + R1 = 6.
Eq1: I2R1 + R1 = 5.3.
Diode disconnected:
V2 + I2*R1 = 6 Volts.
2 + I2R1 = 6.
Eq2: I2R1 = 4.
In Eq1, replace I2H1 with 4:
4 + R1 = 5.3.
R1 = 1.3k = 1300 Ohms.
In Eq2, replace R1 with 1.3k:
I2*1.3k = 4.
I2 = 3.1 mA.
R2 = V2/I2 = 2/3.1 = 0.65k = 650 Ohms.
Rth = R1*R2(R1+R2)=1300*650/(1300+650)= 433 Ohms.
r
Vd + (I2+Id)R1 = 6 Volts.
0.7 + (I2+1.0)R1 = 6.
0.7 + I2*R1 + R1 = 6.
Eq1: I2R1 + R1 = 5.3.
Diode disconnected:
V2 + I2*R1 = 6 Volts.
2 + I2R1 = 6.
Eq2: I2R1 = 4.
In Eq1, replace I2H1 with 4:
4 + R1 = 5.3.
R1 = 1.3k = 1300 Ohms.
In Eq2, replace R1 with 1.3k:
I2*1.3k = 4.
I2 = 3.1 mA.
R2 = V2/I2 = 2/3.1 = 0.65k = 650 Ohms.
Rth = R1*R2(R1+R2)=1300*650/(1300+650)= 433 Ohms.
r
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.