Asked by Zach
ΔT = T(mix) - T(initial)
And the equations is:
HCl(aq)+ NaOH(aq) => NaCl(aq) + H2O(l)
And T(mix) = 37 C
50.0 mL of 2.0M HCl = 23.7 C
50.0 mL of 2.0M NaOH = 23.5 C
How do I find T(initial), do I just use their averages? Thanks
And the equations is:
HCl(aq)+ NaOH(aq) => NaCl(aq) + H2O(l)
And T(mix) = 37 C
50.0 mL of 2.0M HCl = 23.7 C
50.0 mL of 2.0M NaOH = 23.5 C
How do I find T(initial), do I just use their averages? Thanks
Answers
Answered by
Dr Russ
As they are the same volume it is fine to average the two temperatures.
Especially as the subtraction
(37-23.6)C = 13.4C which is 13C to zero dp. (The 37C with zero dp governs the number of dps in the answer).
Especially as the subtraction
(37-23.6)C = 13.4C which is 13C to zero dp. (The 37C with zero dp governs the number of dps in the answer).
There are no AI answers yet. The ability to request AI answers is coming soon!