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A concave mirror produce six times magnified image virtual of an object placed at 5cm in front in it. Where is the image formed ?
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Anonymous
A concave mirror produce six times magnified image virtual of an object placed at 5cm in front in it. Where is the image formed ?
If ‘ho’ is the height of the object and ‘hi’ is the height of the image, then the magnification M produced by a spherical mirror is given by
M=hi/ho.
The magnification M is also related to the object distance ‘do’ and the image distance ‘di’.
M= - di/do.
ho is positive, as the object is usually places above the principle axis;
hi > 0 - for virtual images,hi<0 - for real images
When the image is virtual, it is erect so the height of the image hi >0 which results M >0
M=di/do => di = M•do=6•5=30 cm
If ‘ho’ is the height of the object and ‘hi’ is the height of the image, then the magnification M produced by a spherical mirror is given by
M=hi/ho.
The magnification M is also related to the object distance ‘do’ and the image distance ‘di’.
M= - di/do.
ho is positive, as the object is usually places above the principle axis;
hi > 0 - for virtual images,hi<0 - for real images
When the image is virtual, it is erect so the height of the image hi >0 which results M >0
M=di/do => di = M•do=6•5=30 cm
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