A roller coaster cart of mass m = 293 kg starts stationary at point A, where h1 = 23.3 m and a while later is at B, where h2 = 8.4 m. The acceleration of gravity is 9.8 m/s^2.

Question

What is the speed of the cart at B, ignoring the effect of friction?

Answer 1

g (change in h) = (1/2)v^2
or
v = sqrt (2 g*change in h)

(note - m is irrelevant. That is lucky or a full car would be faster than a light one)