Asked by EDWARD,ESOBUNETA
what is the percent by mass of solution (d =1,3g/ml) of urea ((NH2)2CO) with molarity 8,4mol/l?
Answers
Answered by
DrBob222
% w/w = (grams solute/g solution)*100 = ?.
M = 8.4 mols/L.
mols = grams/molar mass so g = mols x molar mass = 8.4 x 62 = approx 521 g in the solution so g solute = approx 521.
The solution has a mass of 1.3g x 1000 = approx 1300 grams.
Now % = approx 521/1300)*100 = ?
M = 8.4 mols/L.
mols = grams/molar mass so g = mols x molar mass = 8.4 x 62 = approx 521 g in the solution so g solute = approx 521.
The solution has a mass of 1.3g x 1000 = approx 1300 grams.
Now % = approx 521/1300)*100 = ?
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