Question
A wood column is 5.5 in. square in cross section and 12 ft long. Its modulus of elasticity is 1.3 × 106 psi. How much will the column shorten under a compressive load of 36,000 lb?
Answers
delta L/L = F/area / E
delta L = 144 in * 36*10^3 lb /5.5 in^2/1.3*10^6
= 725 * 10^-3
= .724 inches
(scary! probably fails under buckling but we were not asked) )
delta L = 144 in * 36*10^3 lb /5.5 in^2/1.3*10^6
= 725 * 10^-3
= .724 inches
(scary! probably fails under buckling but we were not asked) )
Thank you so much!
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