Asked by Mohan
How long would it take an investment of $6000 to amount to $9000 if interest is earned at 7% compounded continuously ?.
Answers
Answered by
Mohan
1. Ask yourself what you want to find ? - You want to find time ( how long it would take )
2.Clue in question - Continuous compounding
3.Use formula FV=PV.e(r.t)
Where FV=Future Value, PV=present value, e=exponent (ln) , r=rate expressed as a decimal , t=time in years
4.Plugging in the information given
9'000=6000.e(.07.t)
9'000/6000=e(.07t)
1.5=e(.07t)
Taking ln
ln(1.5)=lne (lne=1)(.07t)
using scientific cal(ln1.5).40546=1(.07t)
.40546/.07=t
5.8=t
5.8 years or 5 years 9 months and 18 days
2.Clue in question - Continuous compounding
3.Use formula FV=PV.e(r.t)
Where FV=Future Value, PV=present value, e=exponent (ln) , r=rate expressed as a decimal , t=time in years
4.Plugging in the information given
9'000=6000.e(.07.t)
9'000/6000=e(.07t)
1.5=e(.07t)
Taking ln
ln(1.5)=lne (lne=1)(.07t)
using scientific cal(ln1.5).40546=1(.07t)
.40546/.07=t
5.8=t
5.8 years or 5 years 9 months and 18 days
Answered by
Reiny
correct , small point .....
after 1.5 = e^(.07t)
ln 1.5 = .07 lne
.07t = ln 1.5 , since lne = 1
t = ln 1.5/.07
= 5.79....
don't put (lne=1) as part of your solution line,
after 1.5 = e^(.07t)
ln 1.5 = .07 lne
.07t = ln 1.5 , since lne = 1
t = ln 1.5/.07
= 5.79....
don't put (lne=1) as part of your solution line,
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