Asked by Emma

2.) A sports car is advertised to be able to stop in a distance of 50m from a speed of 90 km/h. What is its acceleration in m/s^2? How many g's is this (g=9.80 m/s^2)
Answered by Emma
I really don't understand how to begin with this question. Struggling at the moment. Any help would be much appreciated!!!!
Answered by bobpursley
change the speed to m/s
speed=90km/hr=90,000m/3600 sec solve that.

Vf=0 (stopped)
vf^2=vi^2+2ad solve for a.

How many g's? divide by 9.8
Answered by Emma
so what do I put into the equation :

vf^2=vi^2+2ad solve for a.

I'm confused on the question how many g's ?
g=9.80 m/s^2 so wouldn't dividing by 9.8 make the how many g's =0 ZERO?
Answered by Damon
Yes acceleration in m/s^2 /9.81 = number of g s
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