Asked by John
In the expression ln(3-x)+ln(3+x) what is the highest possible number that x can be?
I got to this point: ln(9-x^2) but what now? it seems to me that there is an asymptote at x = 3, so the answer is 2.9999999... but it can't be repeating because that would make it 3, however, if it's not repeating, i can always make a bigger number by adding another 9 on the end. So how is this solvable?
I got to this point: ln(9-x^2) but what now? it seems to me that there is an asymptote at x = 3, so the answer is 2.9999999... but it can't be repeating because that would make it 3, however, if it's not repeating, i can always make a bigger number by adding another 9 on the end. So how is this solvable?
Answers
Answered by
Damon
I do not know any better than you do and suspect that they want you to say 3 although we both know that it can not quite be 3.
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