Asked by Anonymous
Find the product of 9 -5i and its complex conjugate
Answers
Answered by
Damon
(9-5i)(9+5i) = 81+25 = 106
note
(a-b)(a+b) = a^2 - b^2
but
i^2 = -1
so
(a-bi)(a+bi) = a^2-b^2i^2 = a^2+b^2
note
(a-b)(a+b) = a^2 - b^2
but
i^2 = -1
so
(a-bi)(a+bi) = a^2-b^2i^2 = a^2+b^2
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