If n(AuBuC)=12 and n(AuB)=8,find n(A'nB'nC). Solution n(A'nB'nC)=12 -8 =4

Answer 1

n(AuBuC)=12
n(AuB)=8, so n(C)=4

n(A'uB'nC)=n((AuB)'nC)

That help?

Answer 2

How did you get the union of the three sets