area = 2 * 2.8 = 5.6 m^2
force = area * difference in pressure
= 5.6 * (1.013 - .96) * 10^5
= .297 * 10^5 Newtons
= 2.97*10^4 Newtons
that is about the weight of a 3000 kg mass.
the window is history
force = area * difference in pressure
= 5.6 * (1.013 - .96) * 10^5
= .297 * 10^5 Newtons
= 2.97*10^4 Newtons
that is about the weight of a 3000 kg mass.
the window is history
Net Force = Pressure Difference x Area
Given:
Pressure Difference (ΔP) = 1.013 ✕ 10^5 Pa - 0.960 ✕ 10^5 Pa
Area (A) = 2.0 m x 2.8 m
First, let's calculate the pressure difference:
ΔP = 1.013 ✕ 10^5 Pa - 0.960 ✕ 10^5 Pa
ΔP = 0.053 ✕ 10^5 Pa
Now, we can calculate the net force:
Net Force = ΔP x A
Net Force = 0.053 ✕ 10^5 Pa x (2.0 m x 2.8 m)
Multiplying the values:
Net Force = 0.053 ✕ 10^5 Pa x 5.6 m^2
Net Force = 0.2968 ✕ 10^5 Pa⋅m^2
Simplifying:
Net Force = 2.968 ✕ 10^4 N
Therefore, the magnitude of the net force exerted on the window is approximately 2.968 ✕ 10^4 Newtons.
1. Start by calculating the pressure difference caused by the storm:
ΔP = P2 - P1
ΔP = (0.960 ✕ 10^5 Pa) - (1.013 ✕ 10^5 Pa)
ΔP = -0.053 ✕ 10^5 Pa (note the negative sign indicates a decrease in pressure)
2. Next, calculate the force exerted on the window using the relationship between pressure, force, and area:
F = ΔP × A
F = (-0.053 ✕ 10^5 Pa) × (2.0 m × 2.8 m)
F = -2.968 ✕ 10^5 N
Therefore, the magnitude of the net force exerted on the window is approximately 2.968 ✕ 10^5 N. Note that the negative sign indicates that the force is directed inward, towards the apartment.