Asked by TODOKO
the probability that a key component of a stand -by generator will fail during a power outage is q. A generator works if at least half of its key component work.Assuming that the the generator has four key components. find the probability that the generator will work
Answers
Answered by
Damon
All of the parts have to work.
probability of part failing =q
probability of part working = (1-q)
4 parts, binomial distribution
4Ck = 4!/[k!(4-k)!]
4C4 = 1 , 4C3= 4 , 4C2= 6
P4 of 4 working = 1 (1-q)^4 q^0= (1-q)^4
P3 of 3 working = 4 (1-q)^3 q^1
P2 of 2 working = 6 (1-q)^2 2^2
add those
probability of part failing =q
probability of part working = (1-q)
4 parts, binomial distribution
4Ck = 4!/[k!(4-k)!]
4C4 = 1 , 4C3= 4 , 4C2= 6
P4 of 4 working = 1 (1-q)^4 q^0= (1-q)^4
P3 of 3 working = 4 (1-q)^3 q^1
P2 of 2 working = 6 (1-q)^2 2^2
add those
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