Asked by Jose
I am standing on the roof of a building with a pea shooter, and I shoot a pea up into the air from a height of 80 feet. The pea reaches its maximum height 2 seconds after I shoot, then falls to the ground.
Give the position of the pea as a function of time
Give the position of the pea as a function of time
Answers
Answered by
Damon
in foot system g = -32 ft/s^2
Hi = 80
v = Vi - 32 t
at max height v = 0
so Vi = 32 t at top
so Vi = 32 * 2 = 64 ft/s
h = Hi + Vi t - 16 t^2
h = 80 + 64 t - 16 t^2
h = 80 + 16 t^2 at top when
Hi = 80
v = Vi - 32 t
at max height v = 0
so Vi = 32 t at top
so Vi = 32 * 2 = 64 ft/s
h = Hi + Vi t - 16 t^2
h = 80 + 64 t - 16 t^2
h = 80 + 16 t^2 at top when
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