Asked by Sanaya
Compute the surface area of revolution about the x-axis over the interval.
y = x^2, [0, 4]
Is it (pi/12)(65^2 - 65)^(3/2)?
y = x^2, [0, 4]
Is it (pi/12)(65^2 - 65)^(3/2)?
Answers
Answered by
Sanaya
Oops.. The subject for this one is calculus, not chemistry
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