Asked by Lucy X
Can someone check my answer?
5x^3 - 40
=5(x^3-8)
=5(x-2)(x^2+2x+4)
Also, how do you factor x^6-y^6 as a difference of cubes?
As a difference of squares, is it (x^3+y^3)(x^3-y^6)?
5x^3 - 40
=5(x^3-8)
=5(x-2)(x^2+2x+4)
Also, how do you factor x^6-y^6 as a difference of cubes?
As a difference of squares, is it (x^3+y^3)(x^3-y^6)?
Answers
Answered by
Damon
Yes.
typo: (x^3-y^3)
typo: (x^3-y^3)
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