so |2.5 - 45t| = .5
2.5 - 45t = .5 OR -2.5 + 45t = .5
-45t = -2 OR 45t = 3
t = 2/45 hrs or t = 3/45 hrs
which is 2 2/3 minutes or in 4 minutes
John is at a car show. Beginning 2.5 miles away, a car travelling at a constant 45 miles per hour approaches and then passes John. The distance between John and the car can be represented by the equation d = |2.5 – 45t|. At what times is the car 0.5 miles from John?
Please help me solve this! What are the steps in solving it? Please help?! Thanks! (=
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