Question
Aris is twice as old as Rico while Jay is 24 years younger than Aris. In half of Aris' age six years ago was three less than one-half the sum of Rico's age in four years and Jay's present age, find the ages of each.
Answers
Reiny
Rico's age now: x
Aris' age now: 2x
Jay's age: 2x-24
six years ago Aris was 2x-6
in four years Rico's age will be x+4
(1/2)(2x-6) = (1/2)(x+4 + 2x-24) - 3
2x-6 = 3x - 20 - 6
-x = -20
x = 20
present ages:
Rico = 20
Aris = 40
Jay = 16
Aris' age now: 2x
Jay's age: 2x-24
six years ago Aris was 2x-6
in four years Rico's age will be x+4
(1/2)(2x-6) = (1/2)(x+4 + 2x-24) - 3
2x-6 = 3x - 20 - 6
-x = -20
x = 20
present ages:
Rico = 20
Aris = 40
Jay = 16