Asked by Hikari
Aris is twice as old as Rico while Jay is 24 years younger than Aris. In half of Aris' age six years ago was three less than one-half the sum of Rico's age in four years and Jay's present age, find the ages of each.
Answers
Answered by
Reiny
Rico's age now: x
Aris' age now: 2x
Jay's age: 2x-24
six years ago Aris was 2x-6
in four years Rico's age will be x+4
(1/2)(2x-6) = (1/2)(x+4 + 2x-24) - 3
2x-6 = 3x - 20 - 6
-x = -20
x = 20
present ages:
Rico = 20
Aris = 40
Jay = 16
Aris' age now: 2x
Jay's age: 2x-24
six years ago Aris was 2x-6
in four years Rico's age will be x+4
(1/2)(2x-6) = (1/2)(x+4 + 2x-24) - 3
2x-6 = 3x - 20 - 6
-x = -20
x = 20
present ages:
Rico = 20
Aris = 40
Jay = 16
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