Asked by E
The rate of change of the population of a small town is dP/dt=kP
Where P is the population, t is the time in years and k is the growth rate.
If P=20000 when t=3 and P=30000 when t=5, what is the population when t=10?
Round your answer to the nearest integer.
Where P is the population, t is the time in years and k is the growth rate.
If P=20000 when t=3 and P=30000 when t=5, what is the population when t=10?
Round your answer to the nearest integer.
Answers
Answered by
Damon
Oh, well, when the rate is proportional to the amount, we have an e^kx kind of a thing
P = Pi e^kt
at t = 3
20,000 = Pi e^3k
at t = 5
30,000 = Pi e^5t
so
3/2 = e^5k/e^3k = e^2k
so
ln (1.5) = 2 k
got it?
P = Pi e^kt
at t = 3
20,000 = Pi e^3k
at t = 5
30,000 = Pi e^5t
so
3/2 = e^5k/e^3k = e^2k
so
ln (1.5) = 2 k
got it?