Asked by lexi
In a lab experiment, 45 grams of a metal are heated from 22⁰C to 78⁰C by the addition of 450 J of heat. What is the specific heat of the metal? Show all calculations leading to an answer.
Answers
Answered by
Damon
heat in = specific heat * change in temp * mass
450 J = C * (78-22) (.045 )
if C is Joules /kg deg C
C = 450/(56*.045)
= 178.6 J/KgC
by the way iron is 450, lead is 130
if your text uses grams then
.1786 J/gC
450 J = C * (78-22) (.045 )
if C is Joules /kg deg C
C = 450/(56*.045)
= 178.6 J/KgC
by the way iron is 450, lead is 130
if your text uses grams then
.1786 J/gC
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