Asked by Amanda

Two ice skaters stand at rest in the center of an ice rink. When they push off against one another the 61-kg skater acquires a speed of 0.63 m/s .
If the speed of the other skater is 0.86 m/s , what is this skater's mass?
Answered by Damon
momentum is zero before so zero after.

61*.63 + m* -.86 = 0
note speeds are opposite so velocity of one or the other is negative

m = 61 (.63/.86)
Answered by Ahmad alajmi
32. Two ice skaters stand at rest in the center of an ice rink. When they push off against each 45-kg skater acquires a speed of 0.62 m/s. If the speed of the other skater is 0.89 m/s, what is that skater's mass?
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