Asked by nuzhat
ahmed throws a ball at initial velocity of 36 meter per second.assuming the ball is caught at the same height at which it was released. calculate the maximum distance the ball can reach.
Answers
Answered by
Henry
a football thrown at 45o has max range:
Range = Vo^2*sin(2A)/g=36^2*sin(90)/9.8 = 132.2 m.
Range = Vo^2*sin(2A)/g=36^2*sin(90)/9.8 = 132.2 m.
Answered by
Anonymous
U Coll out answer please
Answered by
Anonymous
Ahmed throws a ball at an initial velocity of 25m/s.calculate the maximum distance the ball can reach assuming the ball is caught at the same height at which it was released.
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