Asked by John Oben
A molecule consists of two atoms. The atoms have masses of 20 u and 10 u and are 1.08 *10^-10 m apart. How far from the first atom is the center of mass of the molecule?
Can someone help please I tried:
(20u*(1.08 *10^-10m)) + (10u*(1.08 *10^-10))/ (20u+10u) and just got 1.08 *10^-10m again. That isn't right, I know thta it should be closer to the first atom I understand that but cant calculate it.
Can someone help please I tried:
(20u*(1.08 *10^-10m)) + (10u*(1.08 *10^-10))/ (20u+10u) and just got 1.08 *10^-10m again. That isn't right, I know thta it should be closer to the first atom I understand that but cant calculate it.
Answers
Answered by
Damon
20 * x = 10 (1.08 -x)
20 x + 10 x = 10.8
30 x = 10.8
x = .36
so
.36*10^-10 = 3.6 * 10^-11 meters
20 x + 10 x = 10.8
30 x = 10.8
x = .36
so
.36*10^-10 = 3.6 * 10^-11 meters
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.