Asked by Shannon
A boat left dock A, traveled north for 10 miles, then 45 East of north for 20 miles and docked at B.
A.How far north did the boat travel? How far east did it travel? B. Find the magnitude and direction of the direct-path vector AB.
a. North 24.1 East 14.1
b. 22.4 magnitude 45 East of North
A.How far north did the boat travel? How far east did it travel? B. Find the magnitude and direction of the direct-path vector AB.
a. North 24.1 East 14.1
b. 22.4 magnitude 45 East of North
Answers
Answered by
Damon
b can NOT be 45 degrees and the magnitude MUST be bigger than 24.1
north = 10 + 20 cos 45 = 24.1 agree
east = 20 sin 45 = 14.1 agree
mag = sqrt (24.1^2+14.1^2) = 27.94
tan deg e of n = 14.1/24.1
so deg e of n = 30.3 degrees East of North
north = 10 + 20 cos 45 = 24.1 agree
east = 20 sin 45 = 14.1 agree
mag = sqrt (24.1^2+14.1^2) = 27.94
tan deg e of n = 14.1/24.1
so deg e of n = 30.3 degrees East of North
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