Ask a New Question

Question

A 1000Kg car is traveling at 40 m/s.
a.) if the car stops in 20 seconds, what is the deceleration rate?
b.) what friction force will stop the car in 20 seconds?
9 years ago

Answers

Damon
acceleration = (final velocity - initial velocity)/change in time

a = (0 - 40) m/s /20 s

a = - 2 m/s^2

F = m a
F = 1000(-2) = -2000 Newtons
9 years ago

Related Questions

A 1000kg car is traveling along a level road at 20.00ms, when the brakes are applied long enough to... A 1000kg car accelerates from rest to 30m/s over a distance of 20m. a) ignoring friction and a... Car A has a mass of 1000kg and a speed of 60km/h, and car b has a mass of 2000kg and a speed of 30km... a 1000kg car goes over the top of a hill with a radius curvature equal to 40.0m. At the top of the... how far will a 1000kg car travel in 10 sec if it is accelerated from rest by a force of 5000N A car with a mass of 1000kg is travelling at a constant velocity. The force from the engine is 200Ne... A 1000kg car is driving toward the north along a straight horizontal road at a speed of 20.0 m/s. Th... A car weighing 1000kg is going up an incline with a slope of 2 in 25 at a steady speed of 18kmph.If... A car weighing 1000kg is on slope that makes an angle 30° with the horizontal.the component of car's... A 1000kg car is travelling down at a 25° slope. At the instant that time speed is 13m/s,the driver a...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use