acceleration = (final velocity - initial velocity)/change in time
a = (0 - 40) m/s /20 s
a = - 2 m/s^2
F = m a
F = 1000(-2) = -2000 Newtons
A 1000Kg car is traveling at 40 m/s.
a.) if the car stops in 20 seconds, what is the deceleration rate?
b.) what friction force will stop the car in 20 seconds?
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